You did not make "test" large enough to accept an index of 50 or any of the other numbers in x for that matter. On the first pass through that loop you to assigned to the 50 to the 50th element in test. If you wanted to assign 50 to the first element of test the you should look at the seq_along function:

> x <- matrix( c(50,100,200,300,900,2343) ,ncol = 1)
> for (i in seq_along(x) ){
+ test [i] <- x[i]
+ }
> test
     [,1]
[1,]   50
[2,]  100
[3,]  200
[4,]  300
[5,]  900
[6,] 2343



On Sep 27, 2009, at 11:45 AM, Marcio Resende wrote:


Dear John,
What I am trying to do is a genetic analysis and the "i" in my cycle are the
numbers of markers I am testing.
I know the code is not right, but what i wanted to do was to fill this 6 row
matrix with the numbers in x
So basically I wanted the cycle to loop only with the values on x
(50,100,200,300,900,2343) and not the the rest of the values
Do you know how to do it?

In the example I wanted my final test matrix to be
[50
100
200
300
900
2343]
dim(test) <- still 6x1

And probably all zeroes, right?


Thanks for the help




jholtman wrote:

It is unclear exactly what you are trying to do.  Since your 'test'
matrix is only 6 rows in length, then when you extend it by trying to
store into 50 for example, it will fill in the rest of the new values
with NA.  Can you explain what you think the code is supposed to do?
It is doing exactly what you are asking it to do with the script you
provided.

On Sun, Sep 27, 2009 at 10:09 AM, Marcio Resende
<mresende...@yahoo.com.br> wrote:

Hi Tobias, thanks for the help,
the code I am using is quite long, but basically what I tried to do was

test <- matrix(0,6,1)
x <- matrix( c(50,100,200,300,900,2343) ,ncol = 1)
for (i in x){
test [i] <- (i)
}

but this code returns NA for all the elements which are not x




Tobias Verbeke-2 wrote:

Hi nice people,

:-)

I would like to do a for cycle but i wish it to assume only the numers
50,
100, 200, 300, 900 and 2343
I tried to do something like

x <- c(50,100,200,300,900,2343)
for (i in x){
#.....
}

But it didnĀ“t work

If you would use a reproducible code example we
could point out where the error comes from;
otherwise we can only tell this should work;
try

x <- c(50,100,200,300,900,2343)
for (i in x){
   cat(i^2, "\n")
}
# 2500
# 10000
# 40000
# 90000
# 810000
# 5489649

HTH,
Tobias

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--
Jim Holtman
Cincinnati, OH
+1 513 646 9390

What is the problem that you are trying to solve?

______________________________________________
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PLEASE do read the posting guide
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and provide commented, minimal, self-contained, reproducible code.



--
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______________________________________________
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.

David Winsemius, MD
Heritage Laboratories
West Hartford, CT

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