Last one for you guys:
The command:
length(gregexpr('cus','hocus pocus')[[1]])
[1] 2
returns the number of times the substring 'cus' appears in 'hocus pocus'
(which is two)
It's returning the number of **disjoint** matches. So:
length(gregexpr('aa','aaa')[[1]])
[1] 1
returns 1.
**What I want to do:**
I'm looking for a way to count all occurrences of the substring, including
overlapping sets (so 'aa' would be found in 'aaa' two times, because the
middle 'a' gets counted twice).
Any ideas would be much appreciated!!
Signing off and thanks for all the great assistance,
Jonathan
[[alternative HTML version deleted]]
______________________________________________
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
