On Jan 7, 2010, at 8:03 AM, varend...@gmail.com wrote:

Hello all,


Firstly, thanks a lot for all your efforts,
the cbind function was very useful.

I tried all you told me, but I couldn't make it work in the way I wanted.
I mixed two problems I had, a common mistake.
Sorry if I didn't explain myself good enough.

Here, I post a solution for my problem.
I wanted to avoid the "while" loop but I've finally used it.
Hopefully it is helpfull for someone else.


CODE:
-------------------------------


# This could be my data:

VD1 <- c(12, 34, 45, 7, 67, 45)
VD2 <- c(23, 12, 45, 67, 89, 90)
VD3 <- c(14, 11, 10, 19, 20, 27)
VD4 <- c(16, 22, 23, 29, 27, 28)


# and this is my objective:
# (in this case it is just for 4 vectors)

AIM <- matrix(c(VD1, VD2, VD3, VD4), nrow=4, byrow=TRUE)
print(AIM)

# but I want to use any number of vectors
# VDx when x goes from 1 to n

n <- 4  # for this case.

# A solution:
# build an empty matrix with the desired number of rows (vectors)
# then with a "while" loop fill each row with each vector.

Final.matrix <- matrix(, nrow=n, ncol=6, byrow=TRUE)
print(Final.matrix)

y <- 1
while (y <= n)
{
 c <- eval(parse(text=(paste("VD", sep="", y))))
 Final.matrix[y,] <- c
 y <- y + 1
}

print(Final.matrix)

# If I set "n" as 12 I will get the example I explained at first
# then, by using "cbind()" and "1:n" I add the values of the first column
# as many of you suggested to me

---------------------------------------

If someone comes up with a way to do this avoiding the loop, I'd be very
interested to get to know the solution.


Kind regards,

Vilen

Forestry Engineer


library(fortunes)

> fortune("parse")

If the answer is parse() you should usually rethink the question.
   -- Thomas Lumley
      R-help (February 2005)



An easier way is to use get() along with ls(), using a regex pattern in the latter. That will get you the objects which you can then manipulate as desired.


# see ?regex
> ls(pattern = "^VD[0-9]+$")
[1] "VD1" "VD2" "VD3" "VD4"


# This presumes that each vector is the same length, such that using sapply() will return a matrix rather than a list.
> t(sapply(ls(pattern = "^VD[0-9]+$"), get))
    [,1] [,2] [,3] [,4] [,5] [,6]
VD1   12   34   45    7   67   45
VD2   23   12   45   67   89   90
VD3   14   11   10   19   20   27
VD4   16   22   23   29   27   28

HTH,

Marc Schwartz

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