FAQ 7.31 The precision of a floating point number is about 16 digits and your 'x' is at that limit. If you reduce it, you will see a result:
> x=0.99999999999999999 > 1-x [1] 0 > print(1-x, digits=20) [1] 0 > x=0.99999999999999 > print(1-x, digits=20) [1] 0.00000000000000999200722162641 > On Fri, Jan 8, 2010 at 11:56 AM, Paul Evans <p.evan...@yahoo.com> wrote: > Hi all, > > How can I get R to change the default precision value? For example: > > x=0.99999999999999999 > > 1-x > [1] 0 > > > > > Is there a way that I can get a non-zero value using some parameter, or > some package? > many thanks. > > > > [[alternative HTML version deleted]] > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide > http://www.R-project.org/posting-guide.html<http://www.r-project.org/posting-guide.html> > and provide commented, minimal, self-contained, reproducible code. > -- Jim Holtman Cincinnati, OH +1 513 646 9390 What is the problem that you are trying to solve? [[alternative HTML version deleted]] ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.