Maybe I don't understand the question. I can think of four ways to
count, none of which give me 7:
a <- "Hello World"
b <- "Hello Peter"
#counting duplicates and the space:
sa <- strsplit(a, split="")[[1]]
sb <- strsplit(b, split="")[[1]]
length(which(sb %in% sa == TRUE))
#counting the space but not the duplicates:
sa <- unique(strsplit(a, split="")[[1]])
sb <- unique(strsplit(b, split="")[[1]])
length(which(sb %in% sa == TRUE))
#counting the duplicates but not the space:
sa <- strsplit(a, split="")[[1]]
sa <- sa[-which(sa == " ")]
sb <- strsplit(b, split="")[[1]]
sb <- sb[-which(sb ==" ")]
length(which(sb %in% sa == TRUE))
#not counting duplicates or the space:
sa <- unique(sa)
sb <- unique(sb)
length(which(sb %in% sa == TRUE))
What am I missing?
On Sat, Jan 9, 2010 at 4:51 PM, Laetitia Schmid <laetitia.sch...@gmx.ch> wrote:
> Hi!
> Does anybody know a string function that would calculate how many characters
> two strings share? I.e. ("Hello World","Hello Peter") would be 7.
> Thanks.
> Laetitia
>
> ______________________________________________
> R-help@r-project.org mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>
--
Ista Zahn
Graduate student
University of Rochester
Department of Clinical and Social Psychology
http://yourpsyche.org
______________________________________________
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
