Hi!
I'm definitely not an expert in R (and it's my first reply!), but if I
understand right, I think the aggregate function might do what you're
looking for.
Try ?aggregate to get more info. You might find what you need!
HTH
Ivan
Le 2/8/2010 17:39, Jonathan a écrit :
Hi all,
I'm feeling a little guilty to ask this question, since I've
written a solution using a rather clunky for loop that gets the job
done. But I'm convinced there must be a faster (and probably more
elegant) way to accomplish what I'm looking to do (perhaps using the
"merge" function?). I figured somebody out there might've already
figured this out:
I have a dataframe with two columns (let's call them V1 and V2). All
rows are unique, although column V1 has several redundant entries.
Ex:
V1 V2
1 a 3
2 a 2
3 b 9
4 c 4
5 a 7
6 b 11
What I'd like is to return a dataframe cut down to have only unique
entires in V1. V2 should contain a vector, for each V1, that is the
minimum of all the possible choices from the set of redundant V1's.
Example output:
V1 V2
1 a 2
2 b 9
3 c 4
If somebody could (relatively easily) figure out how to get closer to
a solution, I'd appreciate hearing how. Also, I'd be interested to
hear how you came upon the answer (so I can get better at searching
the R resources myself).
Regards,
Jonathan
______________________________________________
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
______________________________________________
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.