Hi, it's generally considered a bad practice but try this,
eval(parse(text=AA)) library(fortunes) fortune(106) HTH, baptiste On 10 March 2010 07:46, jq81 <jingqia...@gmail.com> wrote: > > My question is represented by the following example. > > For example, I have a character string a, which is defined as > > AA="list(x=1, y=2)" > > I want to take out the content of AA by using some function, so that I can > obtain the following expression automatically. > > list(x=1, y=2) > > Does anyone know how to do it? Thanks a lot, > > > > > > > > > -- > View this message in context: > http://n4.nabble.com/How-to-take-out-the-content-of-character-string-tp1587004p1587004.html > Sent from the R help mailing list archive at Nabble.com. > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > -- ____________________ Baptiste Auguié Departamento de Química Física, Universidade de Vigo, Campus Universitario, 36310, Vigo, Spain tel: +34 9868 18617 http://webs.uvigo.es/coloides ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.