Hi!
It's just this easy:
x=gsub("\t","",x)
For more complex things, it's worth learning some regular expressions
syntax.
Miguel
On Tue, Mar 16, 2010 at 2:50 PM, arnaud chozo <arnaud.ch...@gmail.com>wrote:
> Hi all,
>
> I have a string vector like that: x=c("1\t\t", "2", "3\t\t\t")
> I need to remove all the occurrences of "\t", in order to obtain: x = "1"
> "2" "3"
>
> I'm trying to use the function substring2, and it works for each component,
> for example:
> substring2(x[1], "\t") =""
> gives x = "1" "2" " 3\t\t\t"
>
> I'd like to apply this function to each component and I tried the
> following:
>
> myfun = function(x, i) {
> substring2(x[i], "\t") = ""
> }
>
> lapply(x, myfun)
>
> which gives x="" "" ""
>
> I know that I'm wrong somewhere using lapply, but I can't fix it.
>
> Thanks in advance,
> Arnaud Chozo
>
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>
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