Just read the help page:
?"%in%
"%w/o%" <- function(x,y) x[!x %in% y] #-- x without y
(1:10) %w/o% c(3,7,12)
--
David.
On Mar 21, 2010, at 5:57 PM, Martin Batholdy wrote:
thanks!
Now I have one more question;
How can I do the reverse?
when %in% is == (for two vectors of different lengths); what is the
equivalent to != ?
On 21.03.2010, at 22:33, Erik Iverson wrote:
Martin Batholdy wrote:
Hi,
I would like to compare a column of data with a vector.
I have this data.frame for example;
x <- data.frame(A = c(1:5), B = c(1,1,2,2,2))
Now I have a search vector:
search <- c(1,3,5)
when I now try to get all the data-rows which have a 1, a 3, or a
5 in column A and a 2 in column B, I tried this:
x[x$B == 2 & x$A == search,]
I hoped to get 3 2
5 2
as output.
See ?%in%
x[x$B == 2 & x$A %in% search, ]
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