Rolf Turner wrote: > > > On 24/03/2010, at 12:34 PM, Sharpie wrote: >>> foo <- matrix(0,nrow=3,ncol=3) >>> foo >> [,1] [,2] [,3] >> [1,] 0 0 0 >> [2,] 0 0 0 >> [3,] 0 0 0 >> >>> foo[3,3] <- NA >>> foo >> [,1] [,2] [,3] >> [1,] 0 0 0 >> [2,] 0 0 0 >> [3,] 0 0 NA >> >>> write.csv( foo, file='tst.csv', na = "NaN", row.names = F ) >>> readLines( 'tst.csv' ) >> [1] "\"V1\",\"V2\",\"V3\"" "0,0,0" "0,0,0" >> [4] "0,0,NaN" >> >> Seems to work fine for me. If you post a reproducible example, we could >> probably figure out why it is not working for you. > > > This doesn't work if you have both NAs and NaNs in your data frame and you > want to distinguish between these. I.e. when you read the data back in, > all NAs will have been converted to NaNs. > > Admittedly the OP said he wanted to represent all NAs as NaNs, so your > solution would seem to work for him. > > cheers, > > Rolf Turner >
Aye, it still works if I replace the NA in my matrix with NaN. If there is a mixture of NAs and NaNs, there will be some loss of distinction as you say. However, I can not tell if this is the case from the original post-- hence the need for an example! -Charlie ----- Charlie Sharpsteen Undergraduate-- Environmental Resources Engineering Humboldt State University -- View this message in context: http://n4.nabble.com/Saving-tab-csv-delimited-data-with-NaN-s-tp1679673p1679909.html Sent from the R help mailing list archive at Nabble.com. ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
