You can use predict() by specifying a complete data.frame() for prediction to the argument newdata=. Look:
da <- expand.grid(x1=LETTERS[1:4], x2=1:9) da$y <- rnorm(da$x1) da$y[sample(length(da$y), 5)] <- NA m0 <- lm(y~x1+x2, data=da) predict(m0) # NA not predicted predict(m0, newdata=da) # NA predicted Sincerely. Walmes. ----- ..ooo0 ................................................................................................... ..(....)... 0ooo... Walmes Zeviani ...\..(.....(.....)... Master in Statistics and Agricultural Experimentation ....\_)..... )../.... walmeszevi...@hotmail.com, Lavras - MG, Brasil ............ (_/............................................................................................ -- View this message in context: http://n4.nabble.com/predict-lm-with-NAs-tp1840661p1886457.html Sent from the R help mailing list archive at Nabble.com. ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
