On Apr 22, 2010, at 9:41 AM, Doran, Harold wrote:
I wonder if there is a more efficient way to do this task. Suppose I
have two data frames, such as
d1 <- data.frame(x = c(1,2,3), y = c(4,5,6), z = c(7,8,9))
d2 <- d1[, c('y', 'x')]
The first dataframe d1 has more variables than d2 and the variable
columns are in a different order. So, what I want to do is compare
the two frames on the variables that are common between the two.
First I find the common variables between the two dataframes
common_order <- intersect(colnames(d1), colnames(d2))
Then, I have to put the variables in d2 in the same order as d1 as
d2 <- d2[, common_order]
Then, I keep only the variables in common between d1 and d2 as
d1 <- d1[, common_order]
Then, finally I can do the compare on the common variables now in
the same order.
all.equal(d1, d2)
None of this is horribly difficult, but it requires a couple of
steps that I am wondering might be eliminated.
What you are doing sounds a lot like the operations that merge()
implements in one function.
--
David.
Harold
David Winsemius, MD
West Hartford, CT
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