Hi:
There's always prop.table:
I read in your data as a data frame d. Since prop.table() expects a
matrix/array
as input,
> prop.table(as.matrix(d), 2)
V2 V3 V4
[1,] NaN 0.53846154 0.3636364
[2,] NaN 0.15384615 0.0000000
[3,] NaN 0.07692308 0.2727273
[4,] NaN 0.23076923 0.3636364
where the second argument indicates that you want column proportions.
You can always use round(prop.table(as.matrix(d), 2), 2) to simplify the
output
to two decimal places. (As you can see, Dr. Harding's comment about zero
columns is well placed...)
HTH,
Dennis
On Thu, May 6, 2010 at 10:06 AM, n.via...@libero.it <n.via...@libero.it>wrote:
>
> Dear list,
> Im trying to do the following operation but im not able to do it
> This is my table:
> 1 2 3
> 1 0 7 4
> 2 0 2 0
> 3 0 1 3
> 4 0 3 4
>
> what i would like to do is
>
> divide each row values with the corresponding column' sum,namely:
>
> 1 2 3
> 1 0 0.54 0.36
> 2 0 0.15 0
> 3 0 0.08 0.27
> 4 0 0.23 0.36
>
>
> thanks for your attention
>
>
> [[alternative HTML version deleted]]
>
> ______________________________________________
> R-help@r-project.org mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide
> http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>
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