Hi R users, I have a matrix "m" of the type:
m X4.20.2010 X4.19.2010 X4.16.2010 [1,] 0.008319468 0.00000000 -0.008250825 [2,] 0.005574136 0.01816118 0.073081608 [3,] -0.047830688 0.01612903 -0.030239833 [4,] NA NA NA [5,] 0.008746356 0.02848576 -0.025566107 [6,] -0.007990868 0.00000000 -0.026666667 I want to get the sum of each column. Normally I would do: apply(m,2,sum) but I get: > apply(m,2,sum) X4.20.2010 X4.19.2010 X4.16.2010 NA NA NA This is because of the presence of "NA" in m. How do you the equivalent of > sum(m[1:6,1],na.rm=TRUE) using apply? Many thanks! -- View this message in context: http://r.789695.n4.nabble.com/tapply-function-with-NA-tp2164930p2164930.html Sent from the R help mailing list archive at Nabble.com. ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.