Dear list,
I am puzzled by this,
substitute(expression(x), list(x = factor(letters[1:2])))
# expression(1:2)
Why do I get back the factor levels inside the expression and not the
labels? The following work as I expected,
substitute(expression(x), list(x = letters[1:2]))
# expression(c("a", "b"))
substitute(x, list(x = factor(letters[1:2])))
# [1] a b
# Levels: a b
bquote(.(factor(letters[1:2])))
# [1] a b
# Levels: a b
All the best,
baptiste
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