Dear R users,

I am trying to make this (3 by 10) matrix A

--A----------------------------------------------------

0   0     0    0  1  0  0  0  0  0
0   0     0    0  0  1  0  0  0  0
0   0.5  0.5  0  0  0  0  0  0  0

-------------------------------------------------------

from "mass.func"

--mass.func-------------------------------------------
> mass.func
$`00`
prop
5
1

$`10`
prop
6
1

$`11`
prop
  2   3
0.5 0.5
---------------------------------------------------------

which means that

A[1,5] = 1
A[2,6] =1
A[3,2] = A[3,3] = 0.5

otherwise, zero.

Any suggestion will be greatly appreciated.

Regrads,

Kathryn Lord


p.s.

Here is R code.

------------------------------------------------------------------

> dat <- as.data.frame(matrix( c( 2, 1, 1, 3, 1, 1, 6, 1, 0, 5, 0, 0), 4, 3,
byrow=T))
>  covar <- apply(dat[,-1],1,paste,collapse='')
> sp.dat <- split(dat,covar)
> y.covar <- lapply(sp.dat, "[",1)
>
> prop <- function(prop) { table(prop)/sum(table(prop)) }
> mass.func <- lapply(y.covar,prop)
> mass.func
$`00`
prop
5
1

$`10`
prop
6
1

$`11`
prop
  2   3
0.5 0.5

        [[alternative HTML version deleted]]

______________________________________________
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.

Reply via email to