Dear R users, I am trying to make this (3 by 10) matrix A
--A---------------------------------------------------- 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0.5 0.5 0 0 0 0 0 0 0 ------------------------------------------------------- from "mass.func" --mass.func------------------------------------------- > mass.func $`00` prop 5 1 $`10` prop 6 1 $`11` prop 2 3 0.5 0.5 --------------------------------------------------------- which means that A[1,5] = 1 A[2,6] =1 A[3,2] = A[3,3] = 0.5 otherwise, zero. Any suggestion will be greatly appreciated. Regrads, Kathryn Lord p.s. Here is R code. ------------------------------------------------------------------ > dat <- as.data.frame(matrix( c( 2, 1, 1, 3, 1, 1, 6, 1, 0, 5, 0, 0), 4, 3, byrow=T)) > covar <- apply(dat[,-1],1,paste,collapse='') > sp.dat <- split(dat,covar) > y.covar <- lapply(sp.dat, "[",1) > > prop <- function(prop) { table(prop)/sum(table(prop)) } > mass.func <- lapply(y.covar,prop) > mass.func $`00` prop 5 1 $`10` prop 6 1 $`11` prop 2 3 0.5 0.5 [[alternative HTML version deleted]] ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.