could you just give us the output of dput() for the data you copied in the
mail?
eg dput(seal_dist[,1:100])
and an example of how you want your output. I guess I get what you want to
do, but it's not what your code is doing. And it will be difficult to put
that in a matrix, as you have different labels and different numbers of
TO-levels for different days and HR values.
Cheers
On Tue, Jun 1, 2010 at 3:32 PM, RCulloch <ross.cull...@dur.ac.uk> wrote:
>
> Hi Ivan,
>
> Thanks for your help, your initial suggestion did not work, but that is no
> doubt down to my lack of making sense!
>
> Here is a short example of my dataset. Basically the loop is set up to
> match
> the ID with the TO column based on DIST = 0. So A1 = 2, A1.1 =1, A2 = 4,
> A2.1 = 3. That is fine for HR 9, but for HR 10 the numbers no longer match
> those IDs so I need to loop the data and store each loop - if that makes
> sense.
>
>
> FROM TO DIST ID HR DD MM YY ANIMAL DAY
> 1 1 1 2.63981 'A1' 9 30 9 7 1 1
> 2 1 2 0.00000 'A1' 9 30 9 7 1 1
> 3 1 3 6.95836 'A1' 9 30 9 7 1 1
> 4 1 4 8.63809 'A1' 9 30 9 7 1 1
> 5 1 1 0.00000 'A1.1' 9 30 9 7 7 1
> 6 1 2 2.63981 'A1.1' 9 30 9 7 7 1
> 7 1 3 8.03071 'A1.1' 9 30 9 7 7 1
> 8 1 4 8.90896 'A1.1' 9 30 9 7 7 1
> 9 1 1 8.90896 'A2' 9 30 9 7 1 1
> 10 1 2 8.63809 'A2' 9 30 9 7 1 1
> 11 1 3 2.85602 'A2' 9 30 9 7 1 1
> 12 1 4 0.00000 'A2' 9 30 9 7 1 1
> 13 1 1 8.03071 'A2.1' 9 30 9 7 7 1
> 14 1 2 6.95836 'A2.1' 9 30 9 7 7 1
> 15 1 3 0.00000 'A2.1' 9 30 9 7 7 1
> 16 1 4 2.85602 A2.1' 9 30 9 7 7 1
> 17 1 1 3.53695 'A1' 10 30 9 7 1 1
> 18 1 2 4.32457 'A1' 10 30 9 7 1 1
> 19 1 3 0.00000 'A1' 10 30 9 7 1 1
> 20 1 4 8.85851 'A1' 10 30 9 7 1 1
> 21 1 5 12.09194 'A1' 10 30 9 7 1 1
> 22 1 1 7.44743 'A1.1' 10 30 9 7 7 1
> 23 1 2 0.00000 'A1.1' 10 30 9 7 7 1
> 24 1 3 4.32457 'A1.1' 10 30 9 7 7 1
> 25 1 4 13.16728 'A1.1' 10 30 9 7 7 1
> 26 1 5 16.34761 'A1.1' 10 30 9 7 7 1
> 27 1 1 6.13176 'A2' 10 30 9 7 1 1
> 28 1 2 13.16728 'A2' 10 30 9 7 1 1
> 29 1 3 8.85851 'A2' 10 30 9 7 1 1
> 30 1 4 0.00000 'A2' 10 30 9 7 1 1
> 31 1 5 3.40726 'A2' 10 30 9 7 1 1
> 32 1 1 9.03345 'A2.1' 10 30 9 7 7 1
> 33 1 2 16.34761 'A2.1' 10 30 9 7 7 1
> 34 1 3 12.09194 'A2.1' 10 30 9 7 7 1
> 35 1 4 3.40726 'A2.1' 10 30 9 7 7 1
> 36 1 5 0.00000 'A2.1' 10 30 9 7 7 1
> 37 1 1 0.00000 'MALE1' 10 30 9 7 12 1
> 38 1 2 7.44743 'MALE1' 10 30 9 7 12 1
> 39 1 3 3.53695 'MALE1' 10 30 9 7 12 1
> 40 1 4 6.13176 'MALE1' 10 30 9 7 12 1
> 41 1 5 9.03345 'MALE1' 10 30 9 7 12 1
>
>
> So the loop is:
>
> DIST_LOOP<-matrix(NA,NA,ncol=11)
>
> for (i in 1:33){
> SEL_DAY<-seal_dist[seal_dist[,10]==i,]
> SEL_DAY[i]=dist[i]
> print(paste("DAY", i, "of 33"))
> for (s in 1:11){
> SEL_HR<-SEL_DAY[SEL_DAY[,5]==s,]
> print(paste("HR", s, "of 11"))
> indx <- subset(SEL_HR, SEL_HR$DIST == 0)
> SEL_HR$TO_ID <- indx$ID[match(SEL_HR$TO, indx$TO)]
> DIST_LOOP[i,]<-SEL_HR
> }
> }
>
> But storing the data in the DIST_LOOP matrix doesn't work, I am just told
> in
> another post that a list might be better than a matrix?
>
> I hope this makes more sense!?
>
> Many thanks,
>
> Ross
> --
> View this message in context:
> http://r.789695.n4.nabble.com/storing-output-data-from-a-loop-that-has-varying-row-numbers-tp2238396p2238483.html
> Sent from the R help mailing list archive at Nabble.com.
>
> ______________________________________________
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>
--
Joris Meys
Statistical Consultant
Ghent University
Faculty of Bioscience Engineering
Department of Applied mathematics, biometrics and process control
Coupure Links 653
B-9000 Gent
tel : +32 9 264 59 87
joris.m...@ugent.be
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