Could you provide us with dput(becva$V1[1])?
Cheers
Joris
On Wed, Jun 2, 2010 at 2:07 PM, Petr PIKAL <petr.pi...@precheza.cz> wrote:
> Dear all
>
> I encountered strange problem with regexpr replacement
>
> I made this character object
>
> str <- "02.06.10 12:40 "
>
> > str(str)
> chr "02.06.10 12:40 "
>
> I read in an object which seems to be quite similar
>
> > str(as.character(becva$V1)[1])
> chr "02.06.10 12:40 "
>
> However I can not remove trailing spaces from it
>
> > sub(' +$', '', as.character(becva$V1[1]))
>
> [1] "02.06.10 12:40 "
> > sub(' +$', '', str)
> [1] "02.06.10 12:40"
> >
>
> Do somebody have an idea what to do?
>
> $version.string
> [1] "R version 2.12.0 Under development (unstable) (2010-04-25 r51820)"
>
> on Windows
>
> Regards
> Petr
>
> ______________________________________________
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>
--
Joris Meys
Statistical Consultant
Ghent University
Faculty of Bioscience Engineering
Department of Applied mathematics, biometrics and process control
Coupure Links 653
B-9000 Gent
tel : +32 9 264 59 87
joris.m...@ugent.be
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