Suman take a look if this suffices your purpous x <- data.frame(y=as.factor(sample(0:2,1000,replace=TRUE)),x=runif(1000)) x1 <- x[x$y==0,] x2 <- x[x$y==1,] x3 <- x[x$y==2,]
On Fri, Jun 4, 2010 at 10:29 AM, suman dhara <suman.dhar...@gmail.com>wrote: > Sir, > I have a problem regarding partitioning a matrix.I state my problem as > follows: > > I have a y vector of length say 1000.Variable y has 4 levels say > 0,1,2.Corresponding to each y(response), I have a x-vector(explanatory) as > a > row of X matrix.Now, I want to partition the X matrix into 3 submatrices > say > x1,x2,x3 corresponding to each level of y.Is there any function to do this > in R or how can I do this in R? > > For your convinience I attach a sample version of data. > Use dput() and paste it in your mail > > Thanks, > Suman Dhara > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide > http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > > [[alternative HTML version deleted]] ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
