Arnab mukherji wrote:
Hi,
I have a query about the following:
CONTEXT: if we define:
eq <- y ~ x1 + x2
then is.language(eq) returns true. this works perfectly with commands
such as lm(eq,data=my.data)
THE PROBLEM: Now I have a big data set with about 2000 independent
variables. So I tried to automate this. I can pick off the names of
the variables and insert a plus in between them and get a string.
Thus I have
eq<- y ~ " x1 + x2 + ... +x2000" or eq<-"y ~ " x1 + x2 + ... +x2000"
from either case how can I typecast eq into a langugae object and get
the lm command to work ?
Does anyone have any suggestions?
thanks
Arnab.
Arnab,
Once you have your full formula string constructed you can use:
eq <- eval(parse(text = string))
This will put the model formula into eq.
For example try:
eq <- eval(parse(text = "y ~ x1 + x2"))
See ?eval and ?parse for more information.
Hope that helps.
Regards,
Marc Schwartz
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