Dear Charles, Since you are extracting vectors of the same length from each element of the list, you can use "sapply"
"sapply(measure,function(x){x[1:3]})" after which you can transpose, rename, make into a dataframe as desired. In general you would use "lapply" to apply a function to each element of a list, resulting in new list. best, J.R. Lockwood 412-683-2300 x4941 [EMAIL PROTECTED] http://www.rand.org/methodology/stat/members/lockwood/ > If you found my subject heading to be confusing then I'm sure you'll enjoy > the example I've included below. I find the apply type functions to be > wonderful for avoiding loops but when I use them with existing functions, I > end up using loops anyway to extract the vectors I want. I would appreciate > it if someone could show me how to avoid these loops. Thanks. > > EXAMPLE: > noise<-matrix(data = rnorm(15, mean=0, sd=1), nrow = 5, ncol = 3, > byrow = FALSE, dimnames = NULL) > measure<-apply(noise,2,t.test) > measure > tval<-NULL > df<-NULL > pval<-NULL > for (i in 1:length(measure)){ > tval[i]<-measure[[i]][[1]] > df[i]<-measure[[i]][[2]] > pval[i]<-measure[[i]][[3]]} > data.frame(tval,df,pval) > > Charles E. White, Biostatistician > Walter Reed Army Institute of Research > 503 Robert Grant Ave., Room 1w102 > Silver Spring, MD 20910-1557 > 301 319-9781 > WRAIR Home Page: http://wrair-www.army.mil/ > ______________________________________________ [EMAIL PROTECTED] mailing list https://www.stat.math.ethz.ch/mailman/listinfo/r-help