Dear All, I know I am quite obsessive and downright annoying (I apologize about that, but it's the way I am), but I would like to get my understanding of the way nlme calculates degrees of freedom straight.
For instance, on page 91 in Pinheiro and Bates (2000), on the examle of anova(fm2Machie), how is the sum of DF *Pi* corresponding to the terms estimated at level *i* calculated? In the example presenting anova(fm2Machine), *P1 = 0*. I just fail to see why. Same thing for *P2 = 2* (although this seems intuitive, but intuitive could be miles off the real reason) and *P3 = 0*. Incidentally, should I change the grouping, putting *machine* outside and *worker* inside, would anything change? A second thing: is there any substantial difference between the classical decomposition of DF for an ANOVA and the method used by lme for the interaction between a fixed and a random effect, in case the random variable is nominal and the fixed one continuous? Best regards, Federico Calboli ========================= Federico C.F. Calboli Department of Biology University College London Room 327 Darwin Building Gower Street London WClE 6BT Tel: (+44) 020 7679 4395 Fax (+44) 020 7679 7096 [EMAIL PROTECTED] ______________________________________________ [EMAIL PROTECTED] mailing list https://www.stat.math.ethz.ch/mailman/listinfo/r-help