Tony Plate <[EMAIL PROTECTED]> writes: > Why is the body of the function "X" when I substituted a different > expression for X? Also, given that the body of the function is X, how > does the function evaluate to TRUE since X is not defined anywhere > (except in a list that should have been discarded.) > > This happens with both R 1.7.1 and R 1.8.0 (under Windows 2000). > > (yes, I did discover the function is.R(), but I still want to discover > what's going here.)
I think you are defeating the keep.source mechanism. What you're seeing is not the actual function but its source attribute. Try attributes(this.is.R) <- NULL and see what happens. -- O__ ---- Peter Dalgaard Blegdamsvej 3 c/ /'_ --- Dept. of Biostatistics 2200 Cph. N (*) \(*) -- University of Copenhagen Denmark Ph: (+45) 35327918 ~~~~~~~~~~ - ([EMAIL PROTECTED]) FAX: (+45) 35327907 ______________________________________________ [EMAIL PROTECTED] mailing list https://www.stat.math.ethz.ch/mailman/listinfo/r-help
