Christoph,
I concur with the other respondents who questioned why someone would wish to
calculate the median of a factor. However, with regard to your actual
question, I suspect that median() is giving different answers because the
two vectors are not both factors, i.e., that one of them is a character. Did
you test that?
Yes, I did and find the same like Tony Plate:
> is.factor(fbhint.spss1$V15.SPS) # = column 264 [1] TRUE > mode(fbhint.spss1$V15.SPS) [1] "numeric" > is.factor(fbhint.spss1$V15.SP1) # = column 566 [1] TRUE > mode(fbhint.spss1$V15.SP1) [1] "numeric"
Using S, I have seen quirks in this regard that relate to import procedure
and the value of the first element in the vector. In your case, the first
elements differ in that one is NA while the other is "teils/teils".
It also occurs if the first element is the same. For example "wichtig" in columns 263 and 565.
Regards,
Christoph
______________________________________________ [EMAIL PROTECTED] mailing list https://www.stat.math.ethz.ch/mailman/listinfo/r-help
