Dear R-people! I am using R 1.8.0, under Windows XP.
What I want to do is a date conversion of a character column of a data frame and assign the result as a new column. Simple example: > x <- data.frame(a=c("yesterday","today","tomorrow"), b=I(c("20031111", "20031112", "20031113"))) # convert x$b from character to date: > strptime(x$b, format="%Y%m%d") [1] "2003-11-11" "2003-11-12" "2003-11-13" # trying to make this a new column in x: > x$c <- strptime(x$b, format="%Y%m%d") Error in "$<-.data.frame"(`*tmp*`, "c", value = strptime(x$b, format = "%Y%m%d")) : replacement has 9 rows, data has 3 I have done this before (in R 1.7.0), and I am pretty sure this has been working then. What am I doing wrong here (has something changed concerning the value of strptime() in R 1.8.0)? -Heinrich. ______________________________________________ [EMAIL PROTECTED] mailing list https://www.stat.math.ethz.ch/mailman/listinfo/r-help