These are the 9 elements of POSIXlt. For example, try this to see the 9 components:
unclass(a2) The day of the month, which is what you are looking for, is a2$mday . If you want an 87 element vector of dates you probably want to store them as POSIXct: length(as.POSIXct(a2)) or as chron dates: require(chron) length(chron(as.character(rcptdt))) Note that you could also get the day of the month this way: require(chron) month.day.year(chron(as.character(rcptdt)))$day Also note that your format call can be shortened to format(rcptdt) or as.character(rcptdt) since, at that point, you are not yet dealing with dates. --- Date: Fri, 6 Feb 2004 14:10:46 -0600 From: Siddique, Amer <[EMAIL PROTECTED]> To: R ([EMAIL PROTECTED]) <[EMAIL PROTECTED]> Subject: [R] vector of factors to POSIXlt hello, I have a vector of factors > str(rcptdt) Factor w/ 51 levels "1/10/03","1/13/03",..: > length(rcptdt) [1] 87 which i want to convert to class POSIXlt to extract the day, so: a1<-format(rcptdt,"%m/%d/%y") > length(a1) [1] 87 and: a2<-strptime(a1, "%m/%d/%y") str(a2) `POSIXlt', format: chr [1:87] "2002-04-18" "2002-07-19" "2002-08-02" "2002-08-14" ... > a2[1]-a2[2] Time difference of -92 days but the length differs > length(a2) [1] 9 and i cant update rcptdt... > version _ platform i386-pc-mingw32 arch i386 os mingw32 system i386, mingw32 status major 1 minor 8.1 year 2003 month 11 day 21 language R thanks, amer research analyst disability det. bureau madtown-wi-usa ______________________________________________ [EMAIL PROTECTED] mailing list https://www.stat.math.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html