Here are three different ways (using x as defined in your
post):
with( month.day.year(x), day.of.week(month,day,year) )
do.call( "day.of.week", month.day.year(x) )
as.numeric(x-3)%%7 # uses fact that chron(3) is Sunday
---
Date: Mon, 1 Mar 2004 22:18:33 +0530
From: Ajay Shah <[EMAIL PROTECTED]>
To: r-help <[EMAIL PROTECTED]>
Subject: [R] Find out the day of week for a chron object?
I know that this is correct:
library(chron)
x = dates("01-03-04", format="d-m-y", out.format="day mon year")
print(x)
It gives me the string "01 Mar 2004" which is correct.
I also know that I can say:
print(day.of.week(3,1,2004))
in which case he says 1, for today is monday.
My question is: How do I combine these two!? :-) I have a data file
which is being parsed nicely and read in using the chron() function. I
need to identify fridays and treat them differently. So I need to run
the day.of.week function. But day.of.week() doesn't eat a chron
object, he insists he wants m,d,y. This seems quite odd. Any idea what
I can do?
Thanks,
-ans.
--
Ajay Shah Consultant
[EMAIL PROTECTED] Department of Economic Affairs
http://www.mayin.org/ajayshah Ministry of Finance, New Delhi
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