I suspect that some people still might not have caught why the behavior is a good thing.
We want
any(c(A, B))
to give the same answer as
any(A) || any(B)
This should be the behavior even if all of the elements are in one of the vectors.
This actually is useful in coding, though I can't think of any specific instances at the moment.
Patrick Burns
Burns Statistics [EMAIL PROTECTED] +44 (0)20 8525 0696 http://www.burns-stat.com (home of S Poetry and "A Guide for the Unwilling S User")
Douglas Bates wrote:
"Liaw, Andy" <[EMAIL PROTECTED]> writes:
I wrote:
I was bitten by the behavior of all() when given logical(0): It is TRUE!I guess the behavior is consistent with:
(And any(logical(0)) is FALSE.) Wouldn't it be better to return logical(0)
in both cases?
prod(numeric(0))[1] 1
sum(numeric(0))[1] 0
but why?
The operation applied to a zero-length vector returns the identity element of the operator. The identity element of * is 1, of + is 0, of & is TRUE and of | is FALSE.
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