Well, there ain't no such thing in R .... And your code doesn't
really make sense anyway. You talk about ``a[i]'' where a is
apparently a ***matrix*** (with the same number of columns as the
matrix b, but with fewer --- possibly 0 --- rows). And in such as
setting a[i] has a meaning, but probably not what you want. And
talking about ``a[i] <- 0'' when i is a running index, running in
this case over the empty set (!!!) doesn't make sense either.
Perhaps what you want to accomplish is along something like the
following lines:
a<-b[s>3,]
if(nrow(a)==0) {
result <- 0
} else {
result <- numeric(nrow(a))
for (i in 1:nrow(a)){
result[i] <- 1
}
}
Of course if that's what you're really trying to do, the for-loop
is a silly waste of time. Instead do
a<-b[s>3,]
if(nrow(a)==0) {
result <- 0
} else result <- rep(1,nrow(a))
or slightly more elegantly
a<-b[s>3,]
result <- if(nrow(a)==0) 0 else rep(1,nrow(a))
cheers,
Rolf Turner
[EMAIL PROTECTED]
===+===+===+===+===+===+===+===+===+===+===+===+===+===+===+===+===+===+===
You wrote:
> I'm writing a function which involves a loop. What to write in the "?"
> place would allow it skips the "for loop" and goes to "a[i]<-0".
>
>
> a<-b[s>3,]
>
> if (nrow(a)==0) ?????????????
>
>
> for (i in 1:nrow(a)){
> a[i]<-1
> }
> a[i]<-0
>
>
> Lisa Wang
> Cancer Informatics,
> Ontario Cancer Institute/Princess Margaret Hospital, University Health
> Network;
> Email: [EMAIL PROTECTED]
> Phone: 416 946 4501 ext. 5201
> Fax: 416 946 4619
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