Please read the posting guide that tells you to a) use a meaningful subject line b) give a reproducible example if you can c) read the manuals and help files first
If you have a vector (not a list) of numbers, say x, and you want to center it on the median you can do x <- c(1,2,3,4,5) Then x - median(x) will give you the deviation of x from its median. Note that operations in R is vectorised, so you do not need to to do something like "for(i in 1:5) y[i] <- x[i] - median(x)". Next you want to square this deviation and sum over all elements. d <- x - median(x) sum( d^2 ) Or you can do it in one line as "sum( (x - median(x))^2 )" On Thu, 2004-11-11 at 16:28, Wei Yang wrote: > Hi, > > > > I have a list of numbers. For each of the numbers, I take sum of squares of > the numbers centered on the number chosen. If it is less than a certain > constant, I will take the average of the numbers chosen. > > > > Anyone can give me a sample code. You help will be greatly appreciated. > > > > Peter > > > [[alternative HTML version deleted]] > > ______________________________________________ > [EMAIL PROTECTED] mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html -- Adaikalavan Ramasamy [EMAIL PROTECTED] Centre for Statistics in Medicine http://www.ihs.ox.ac.uk/csm/ Cancer Research UK Tel : 01865 226 677 Old Road Campus, Headington, Oxford Fax : 01865 226 962 ______________________________________________ [EMAIL PROTECTED] mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
