Werner Wernersen wrote:
Hi everybody!
I am sorry to bother you with a question so simple but
I think there might be a better solution:
I have a matrix of size 360x501 where I want to check
the value of each 5th column of each row and replace it (and the 6th, 7th,
8th column) by zero if the value is less than 1000. I have written a double loop
to do that but that requires a lot of time.
Is there a faster way to achieve this?
Two ways to interpret your question:
1) if col5 < 100 replace col5 & col6 & col7 & col8 by 0:
X[X[,5] < 1000, 5:8] <- 0
2) if col5 < 100 replace col5 by 0, if col6 < 100 replace col6 by 0, ...:
for(i in 5:8) X[X[,i] < 1000, i] <- 0
Uwe Ligges
Thanks, Werner
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