Steve Vejcik wrote:
Thanks for your advice. Unfortunately, your answers are inconsistent:
as.numeric("0x1AF0") returns a decimal value for a hex string. I'd like
to do the opposite-use hex notation to represent a decimal.
e.g.
x<-0x000A
y<-0x0001
x+y=0x00B
Cheers.
you can use chcode() to define hex.to.dec(), dec.to.hex() and sum.hex()
to operate with hex numbers.
Peter Wolf
----------------------------------------------
<<define chcode>>=
chcode <- function(b, base.in=2, base.out=10, digits="0123456789ABCDEF"){
# change of number systems, pwolf 10/02
# e.g.: from 2 2 2 2 ... -> 16 16 16 ...
digits<-substring(digits,1:nchar(digits),1:nchar(digits))
if(length(base.in)==1) base.in <- rep(base.in, max(nchar(b)-1))
if(is.numeric(b)) b <- as.character(as.integer(b))
b.num <- lapply(strsplit(b,""), function(x) match(x,digits)-1 )
result <- lapply(b.num, function(x){
cumprod(rev(c(base.in,1))[ 1:length(x) ] ) %*% rev(x)
} )
number<-unlist(result)
cat("decimal representation:",number,"\n")
if(length(base.out)==1){
base.out<-rep(base.out,1+ceiling(log( max(number), base=base.out ) ) )
}
n.base <- length(base.out); result <- NULL
for(i in n.base:1){
result <- rbind(number %% base.out[i], result)
number <- floor(number/base.out[i])
}
result[]<-digits[result+1]
apply(result, 2, paste, collapse="")
}
@
<<define hex.to.dec, dec.to.hex and sum.hex>>=
hex.to.dec<-function(x) as.numeric(chcode(x, base.in=16, base.out=10))
dec.to.hex<-function(x) chcode(x, base.in=10, base.out=16)
sum.hex<-function(x,y) dec.to.hex(hex.to.dec(x) + hex.to.dec(y))
@
quick test:
<<define hex numbers>>=
a<-dec.to.hex(10); print(a)
b<-dec.to.hex(3);print(b)
@
output-start
decimal representation: 10
[1] "0A"
decimal representation: 3
[1] "03"
output-end
@
<<sum of a and b>>=
sum.hex(a,b)
@
output-start
decimal representation: 10
decimal representation: 3
decimal representation: 13
Thu Apr 7 17:31:42 2005
[1] "0D"
output-end
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