Here's a bit of a refinement on Ted's first suggestion. N <- 10000 graphics.off() par(mfrow = c(1,2), pty = "s") for(k in 1:20) { m <- (rowMeans(matrix(runif(M*k), N, k)) - 0.5)*sqrt(12*k) hist(m, breaks = "FD", xlim = c(-4,4), main = k, prob = TRUE, ylim = c(0,0.5), col = "lemonchiffon") pu <- par("usr")[1:2] x <- seq(pu[1], pu[2], len = 500) lines(x, dnorm(x), col = "red") qqnorm(m, ylim = c(-4,4), xlim = c(-4,4), pch = ".", col = "blue") abline(0, 1, col = "red") Sys.sleep(1) }
-----Original Message----- From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] On Behalf Of [EMAIL PROTECTED] Sent: Friday, 22 April 2005 4:48 AM To: Paul Smith Cc: r-help@stat.math.ethz.ch Subject: RE: [R] Using R to illustrate the Central Limit Theorem On 21-Apr-05 Paul Smith wrote: > Dear All > > I am totally new to R and I would like to know whether R is able and > appropriate to illustrate to my students the Central Limit Theorem, > using for instance 100 independent variables with uniform distribution > and showing that their sum is a variable with an approximated normal > distribution. > > Thanks in advance, > > Paul Similar to Francisco's suggestion: m<-numeric(10000); for(k in (1:20)){ for(i in(1:10000)){m[i]<-(mean(runif(k))-0.5)*sqrt(12*k)} hist(m,breaks=0.3*(-15:15),xlim=c(-4,4),main=sprintf("%d",k)) } (On my slowish laptop, this ticks over at a satidfactory rate, about 1 plot per second. If your mahine is much faster, then simply increase 10000 to a larger number.) The real problem with demos like this, starting with the uniform distribution, is that the result is, to the eye, already approximately normal when k=3, and it's only out in the tails that the improvement shows for larger values of k. This was in fact the way we used to simulate a normal distribution in the old days: look up 3 numbers in Kendall & Babington-Smith's "Tables of Random Sampling Numbers", which are in effect pages full of integers uniform on 00-99, and take their mean. It's the one book I ever encountered which contained absolutely no information -- at least, none that I ever spotted. A more dramatic illustration of the CLT effect might be obtained if, instead of runif(k), you used rbinom(k,1,p) for p > 0.5, say: m<-numeric(10000); p<-0.75; for(j in (1:50)){ k<-j*j for(i in(1:10000)){m[i]<-(mean(rbinom(k,1,p))-p)/sqrt(p*(1-p)/k)} hist(m,breaks=41,xlim=c(-4,4),main=sprintf("%d",k)) } Cheers, Ted. -------------------------------------------------------------------- E-Mail: (Ted Harding) <[EMAIL PROTECTED]> Fax-to-email: +44 (0)870 094 0861 Date: 21-Apr-05 Time: 19:48:05 ------------------------------ XFMail ------------------------------ ______________________________________________ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html ______________________________________________ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html