Aleksey Naumov <[EMAIL PROTECTED]> writes: > Dear List, > > I would like to plot a simple legend with two math expressions, e.g. > > plot(0) > legend(1, 0.5, expression(sigma[i], sigma[j])) > > The difficulty is that i and j should be variables rather than strings "i" > and > "j". In other words I'd like to do something like: > > i = "A" > j = "B" > legend(1, 0.5, expression(sigma[i], sigma[j])) > > and have "A" and "B" as the actual subscripts. I can substitute the variable > in the expression e.g.: > > legend(1, 0.5, substitute(sigma[i], list(i='A', j='B'))) > legend(1, 0.5, bquote(sigma[.(i)])) > > however, this gives me just one of the two entries in the legend. I cannot > figure out how to include both sigmas in the legend. > > What would be the best way to do something like this? Thank you for your > ideas > or suggestions.
Ick. One of those cases that suggests that our current substitute mechanisms don't quite cut it... However, try i <- "A"; j <- "B" e <- bquote(expression(sigma[.(i)],sigma[.(j)])) plot(0) legend(1,.5,eval(e)) legend(1,-.5,e) # for comparison Thing is, substitute(expression(....),...) returns a call to the "expression" constructor, rather than the expression itself, so you need the eval(). -- O__ ---- Peter Dalgaard Blegdamsvej 3 c/ /'_ --- Dept. of Biostatistics 2200 Cph. N (*) \(*) -- University of Copenhagen Denmark Ph: (+45) 35327918 ~~~~~~~~~~ - ([EMAIL PROTECTED]) FAX: (+45) 35327907 ______________________________________________ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html