hi all
i simply wanted to work with real numbers and thought that (-8)^(1/3) should
work.
sorry for not making the question clearer.
/
allan
Quoting Duncan Murdoch <[EMAIL PROTECTED]>:
> On 7/12/2005 9:29 AM, Robin Hankin wrote:
> > Hi
> >
> > I find that one often needs to keep reals real and complexes complex.
> >
> > Try this:
> >
> > "cuberooti" <-
> > function (x)
> > {
> > if (is.complex(x)) {
> > return(sqrt(x + (0+0i)))
> > }
> > sign(x)* abs(x)^(1/3)
> > }
> >
> >
> > best wishes
> >
> > [see that (0+0i) sitting there!]
>
> I don't understand this.
>
> 1. I don't think you meant to use sqrt() there, did you??
>
> 2. What effect does the 0+0i have? x has already been determined to be
> complex.
>
> Duncan Murdoch
>
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