Dear Ghislain I do not know a general elegant solution, but for some applications the following example may be helpful:
## Artificial data for demonstration: group is fixed, species is random dat <- data.frame(group = c(rep("A",20),rep("B",17),rep("C",24)), species = c(rep("sp1", 4), rep("sp2",5), rep("sp3",5), rep("sp4",6), rep("sp5",2), rep("sp6",5), rep("sp7",3), rep("sp8",3), rep("sp9",4), rep("sp10",6), rep("sp11",6), rep("sp12",6), rep("sp13",6)), area = rnorm(61)) ## You can attach a contrast at your fixed factor of interest "group" ## Create the contrast you like to test (in our case contr.sum for 3 ## levels) mat <- contr.sum(3) ## You can add the names you want to see in the output ## Be carefull that you give the correct names to the concerned ## column. Otherwise there is the big danger of misinterpretation. colnames(mat) <- c(": A against rest", ": B against rest") ## Attatch the contrast at your factor "group" dat[,"group"] <- C(dat[,"group"],mat) ## Now calculate the lme library(nlme) reg.lme <- lme(area ~ group, data = dat, random = ~ 1|species) summary(reg.lme) Maybe someone has a better idea how to do it generally. Hope this helps Christoph Buser -------------------------------------------------------------- Christoph Buser <[EMAIL PROTECTED]> Seminar fuer Statistik, LEO C13 ETH (Federal Inst. Technology) 8092 Zurich SWITZERLAND phone: x-41-44-632-4673 fax: 632-1228 http://stat.ethz.ch/~buser/ -------------------------------------------------------------- Ghislain Vieilledent writes: > Good morning, > > I used in R contr.sum for the contrast in a lme model: > > > options(contrasts=c("contr.sum","contr.poly")) > > Septo5.lme<-lme(Septo~Variete+DateSemi,Data4.Iso,random=~1|LieuDit) > > intervals(Septo5.lme)$fixed > lower est. upper > (Intercept) 17.0644033 23.106110 29.147816 > Variete1 9.5819873 17.335324 25.088661 > Variete2 -3.3794907 6.816101 17.011692 > Variete3 -0.5636915 8.452890 17.469472 > Variete4 -22.8923812 -10.914912 1.062558 > Variete5 -10.7152821 -1.865884 6.983515 > Variete6 0.2743390 9.492175 18.710012 > Variete7 -23.7943250 -15.070737 -6.347148 > Variete8 -21.7310554 -12.380475 -3.029895 > Variete9 -27.9782575 -17.480555 -6.982852 > DateSemi1 -5.7903419 -1.547875 2.694592 > DateSemi2 3.6571596 8.428417 13.199675 > attr(,"label") > [1] "Fixed effects:" > > How is it possible to obtain a return with the name of my factor's levels as > with contr.treatment ? > > Thanks for you help. > > -- > Ghislain Vieilledent > 30, rue Bernard Ortet 31 500 TOULOUSE > 06 24 62 65 07 > > [[alternative HTML version deleted]] > > ______________________________________________ > R-help@stat.math.ethz.ch mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html ______________________________________________ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html