If all vectors in the list have the same length, why not use a matrix? Then
you'd just transpose the matrix if you need to. If you really have to have
it as a list, here's one possibility:
> x <- list("1"=c(a=1, b=2, c=3), "2"=c(a=4, b=5, c=6))
> x
$"1"
a b c
1 2 3
$"2"
a b c
4 5 6
> as.list(as.data.frame(t(matrix(unlist(x), nrow=3))))
$V1
[1] 1 4
$V2
[1] 2 5
$V3
[1] 3 6
Andy
> From: Jan Hummel
>
> Hi.
> Can anyone suggest a simple way to re-sort in R a list of
> vectors of the
> following form?
>
> input
> $"1"
> a b c
> 1 2 3
> $"2"
> a b c
> 4 5 6
>
> Output should be something like:
> "a"
> "1" 1
> "2" 4
> "b"
> "1" 2
> "2" 5
> "c"
> "1" 3
> "2" 6
>
> I've been futzing with mapply(), outer(), split(), rbind()
> and so on but
> haven't found an elegant solution.
>
> Thanks,
> Jan.
>
> P.S. E-mailed CCs of posted replies appreciated.
>
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