Hi Marc, > x = c(1,1,1,2,2,2,3,3,3,3) > unique(x) [1] 1 2 3 >
Being a database guy myself, it took me a while to think "unique" rather than "distinct" -- HTH, Jim Porzak Loyalty Matrix Inc. San Francisco, CA On 9/16/05, Marc Bernard <[EMAIL PROTECTED]> wrote: > Dear All, > > I have a vector x = (1,1,1,2,2,2,3,3,3,3) > I am looking for a function to return a vector containing the distinct > elements of x i,e y = (1,2,3) > > The following code gives the desired results: > > as.numeric(levels(as.factor(x))) > > Is there any other elegant way? > > Thanks, > > B > > > > > --------------------------------- > > > [[alternative HTML version deleted]] > > ______________________________________________ > [email protected] mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html > ______________________________________________ [email protected] mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
