Ron Piccinini wrote:
> Hello,
>
> I have 2700 text files in a folder and need to apply
> the same program/procedure to each individually. I'm
> trying to find how to code something like:
>
> For each file in <Folder> do {<Procedure>}
>
> is there an easy way to do this? other suggestions?
files <- listfiles()
results <- lapply(files, yourprocessing())
where yourprocessing is a function taking as argument a file name and
returning whatever you want.
Kjetil
>
> I have tried to list all the files names in a vector
> e.g.
>
>> listfiles[1:10,1]
>
> 1 H:/Rtest/AXP.txt
> 2 H:/Rtest/BA.txt
> 3 H:/Rtest/C.txt
> 4 H:/Rtest/CAT.txt
> 5 H:/Rtest/DD.txt
> 6 H:/Rtest/DIS.txt
> 7 H:/Rtest/EK.txt
> 8 H:/Rtest/GE.txt
> 9 H:/Rtest/GM.txt
> 10 H:/Rtest/HD.txt
>
> but R doesn't like statements of type
>
>> read.table(file=listfiles[1,1])
>
> since 'file' must be a character string or
> connection...
>
> Any thoughts?
>
> Many thanks in advance,
>
> Ron Piccinini.
>
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