Hi
or use outer
x<-1:10
x<-sample(x)
mat<-outer(x,x,"-") # result with zeroes
matrix(mat[!mat==0],9,9) # get rid of them
will give you a matrix with columns with intended result.
HTH
Petr
On 13 Dec 2005 at 11:53, Robert Burrows wrote:
Date sent: Tue, 13 Dec 2005 11:53:00 -0500 (EST)
From: Robert Burrows <[EMAIL PROTECTED]>
To: Oarabile Molaodi <[EMAIL PROTECTED]>
Copies to: r-help@stat.math.ethz.ch
Subject: Re: [R] help with writing function
> On Tue, 13 Dec 2005, Oarabile Molaodi wrote:
>
> > I'm trying to write a function that takes a vector of length n and
> > then takes the first value of the vector i.e j=1 and forms a new
> > vector of length n (i.e replicate the first value n times). This
> > function will then calculate the absoulte difference of the original
> > vector and the new vector and store the results omitting the
> > difference between the value and itself. This function should be
> > able to repeat the procedure for each of the j's i.e j=2 to n. The
> > results should all be stored together. Below is what I've tried so
> > far but it seems to work only for j=1 .
> >
> > Your help will be highly appreciated.
> > IED<-function(risk){
> > n<-length(risk)
> > i<-c(1:n)
> > Diff<-numeric()
> > for(j in 1:n){
> > relrisk<-risk
> > relrisk[i]<-relrisk[j]
> > Difference<-abs(risk-relrisk)
> > Difference<-Difference[-c(1:j)]
> > Difference<-append(Diff,Difference)
> > return(Difference)
> > }
> > }
>
> How about
>
> "IED" <-
> function(risk){
> n<-length(risk)
> Diff<-numeric(n)
> for(j in 1:n){
> relrisk<-rep(risk[j],n)
> Diff[j]<-sum(abs(risk-relrisk)[-j])
> }
> Diff
> }
>
> --
> Robert Burrows, PhD
> New England Biometrics
> [EMAIL PROTECTED]
>
> ______________________________________________
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Petr Pikal
[EMAIL PROTECTED]
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