Thank you very much for your help but I think there is an error for the
answer to the first problem I spent time on searching the solution but
I failed to find it. I tried to put "which.max" instead of "which.min"
but it doesn't work. I tried to do my best but i didn't have any idea to
solve this problem.
An example :
Num <- c(1,2,4,3,4,4,5,5,5)
Date <- c("1/1/04 0:48","1/1/04 8:02", "1/1/04 1:55", "1/1/04 2:14", "1/1/04
1:19", "1/1/04 1:02", "1/1/04 11:15", "1/1/04 9:06", "1/1/04 10:32")
Place <- c("x1","x1","x4","x3","x4","x4","x5","x5","x5")
X <- c(1,NA,3,2,3,3,6,6,6)
Y <- c(1,NA,7,9,7,7,8,8,8)
toto <- data.frame(Num,Date,Place,X,Y)
toto[order(toto$Num,as.numeric(as.POSIXct(strptime(toto$Date, "%d/%m/%y
%H:%M")))),]
toto <- merge(toto[1:3], unique(na.omit(toto[3:5])),by="Place",all.x=T)
help <- do.call("rbind", lapply(split(toto, toto$Num),
function(x) x[which.min(as.numeric(as.POSIXct(strptime(toto$Date, "%d/%m/%y
%H:%M")))),]))
help
The solution must be
Num <- c(1,2,3,4,5)
Date <- c("1/1/04 0:48","1/1/04 8:02", "1/1/04 2:14", "1/1/04 1:02", "1/1/04
9:06")
Place <- c("x1","x1","x3","x4","x5")
X <- c(1,1,2,3,6)
Y <- c(1,1,9,7,8)
toto <- data.frame(Num,Date,Place,X,Y)
Any suggestion is welcome.
Florent Bonneu.
Jacques VESLOT wrote:
> OK ! so try this:
> merge(toto[1:3], unique(na.omit(toto[3:5])),by="Place",all.x=T)
>
>
> Florent Bonneu a écrit :
>
>> Indeed,
>> X <- c(1,Na,2,3,3,3,6,6)
>> Y <- c(1,Na,9,7,7,7,8,8)
>>
>> I want to obtain one line for each Num. It's not a problem if there
>> are several lines for the same place, because my identifier is Num. I
>> just want to get X and Y well-informed in an other line for the same
>> place. For example, "Num=2" is at the place "x1", like "Num=1", but
>> we don't have the coordinates X and Y for "Num=2". Now, the same
>> coordinates are well-informed for "Num=1", so i want to retrieve this
>> coordinates in my line "Num=2" for my columns X and Y.
>>
>>
>>
>> Jacques VESLOT wrote:
>>
>>> something wrong in X and Y definitions... but this could work:
>>>
>>> do.call("rbind", lapply(split(toto, toto$Num),
>>> function(x) x[which.min(as.POSIXct(strptime(toto$Date, "%d/%m/%y
>>> %H:%M"))),]))
>>>
>>> i don't understand the second query; do you want to keep the first
>>> line when there are several lines for the same place ?
>>>
>>>
>>> Florent Bonneu a écrit :
>>>
>>>> I have two problems for the data processing of my large data base
>>>> (50000 rows). For example, a sample is as follows
>>>>
>>>> Num <- c(1,2,3,4,4,4,5,5)
>>>> Date <- c("1/1/04 0:48","1/1/04 1:52", "1/1/04 1:55", "1/1/04
>>>> 2:14", "1/1/04 3:09", "1/1/04 8:02", "1/1/04 9:05", "1/1/04 9:06")
>>>> Place <- c("x1","x1","x3","x4","x4","x4","x5","x5")
>>>> X <- c(1,””,2,3,3,3,6,6)
>>>> Y <- c(1,””,9,7,7,7,8,8)
>>>>
>>>> toto <- data.frame(Num,Date,Place,X,Y)
>>>>
>>>> The first problem is to keep one line for each Num with the
>>>> “minimum” date. I managed to do it with loops but i would like a
>>>> solution without using loops. It will be better for my large data
>>>> base.
>>>>
>>>> The other one is to retrieve the coordinates ill-informed. For
>>>> example, for the same place “x1”, Num=2 doesn't have X and Y. But,
>>>> we have this information for Num=1.
>>>>
>>>> The example data base must be like this
>>>>
>>>> Num <- c(1,2,3,4,5)
>>>> Date <- c("1/1/04 0:48","1/1/04 1:52", "1/1/04 1:55", "1/1/04
>>>> 2:14", "1/1/04 9:05")
>>>> Place <- c("x1","x1","x3","x4","x5")
>>>> X <- c(1,1,2,3,6)
>>>> Y <- c(1,1,9,7,8)
>>>>
>>>> toto <- data.frame(Num,Date,Place,X,Y)
>>>> Somebody know how to do ?
>>>> Thanks.
>>>>
>>>> Florent Bonneu
>>>> Laboratoire de Statistique et Probabilités
>>>> bureau 148 bât. 1R2
>>>> Université Toulouse 3
>>>> 118 route de Narbonne - 31062 Toulouse cedex 9
>>>> [EMAIL PROTECTED] <mailto:[EMAIL PROTECTED]>
>>>>
>>>> ______________________________________________
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>>>> http://www.R-project.org/posting-guide.html
>>>>
>>>>
>>>>
>>>
>>>
>>>
>>
>
>
>
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