> temp<-data.frame(col1=c(5,10,14,56,7),col2=c(4,2,8,3,34),col3=c(28,4,52,34,67))
> temp
col1 col2 col3
1 5 4 28
2 10 2 4
3 14 8 52
4 56 3 34
5 7 34 67
> as.numeric(as.matrix(temp))
[1] 5 10 14 56 7 4 2 8 3 34 28 4 52 34 67
Whether this works well enough:
> temp <- as.data.frame(matrix(1:(1000*6000), nr=1000))
> dim(temp)
[1] 1000 6000
> date() ; num <- as.numeric(as.matrix(temp)) ; date()
[1] "Mon Jan 23 19:40:25 2006"
[1] "Mon Jan 23 19:40:25 2006"
> length(num)
[1] 6000000
Gabor
On Mon, Jan 23, 2006 at 09:49:40AM -0800, r user wrote:
> I have a dataset of 3 columns and 5 rows.
>
> temp<-data.frame(col1=c(5,10,14,56,7),col2=c(4,2,8,3,34),col3=c(28,4,52,34,67))
>
> I wish to convert this to a single column, with
> column 1 on top and column 3 on bottom.
>
> i.e.
>
> 5
> 10
> 14
> 56
> 7
> 4
> 2
> 8
> 3
> 34
> 28
> 4
> 52
> 34
> 67
>
> Are there any functions that do this, and that will
> work well on much larger datasets (e.g. 1000 rows,
> 6000 columns)?
>
> ______________________________________________
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--
Csardi Gabor <[EMAIL PROTECTED]> MTA RMKI, ELTE TTK
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