Is this what you want?  It returns a character vector with the values:

> generate.index<-function(n.item){
+ .return <- character()  # initialize vector
+ for (i in 1:n.item)
+    {
+        for (j in ((i+1):n.item))
+            {
+ # concatenate the results
+ .return <- c(.return,
paste("i",formatC(i,digits=2,flag="0"),".",formatC(j,digits=2,flag="0"),sep=""))
+
+            }
+
+    }
+    .return
+  }
>
>
> generate.index(10)
 [1] "i001.002" "i001.003" "i001.004" "i001.005" "i001.006" "i001.007"
 [7] "i001.008" "i001.009" "i001.010" "i002.003" "i002.004" "i002.005"
[13] "i002.006" "i002.007" "i002.008" "i002.009" "i002.010" "i003.004"
[19] "i003.005" "i003.006" "i003.007" "i003.008" "i003.009" "i003.010"
[25] "i004.005" "i004.006" "i004.007" "i004.008" "i004.009" "i004.010"
[31] "i005.006" "i005.007" "i005.008" "i005.009" "i005.010" "i006.007"
[37] "i006.008" "i006.009" "i006.010" "i007.008" "i007.009" "i007.010"
[43] "i008.009" "i008.010" "i009.010" "i010.011" "i010.010"
>



On 2/4/06, Taka Matzmoto <[EMAIL PROTECTED]> wrote:
>
> Hi R users
>
> I wrote a function that generates some character strings.
>
> generate.index<-function(n.item){
> for (i in 1:n.item)
>    {
>        for (j in ((i+1):n.item))
>            {
>
>
> cat("i",formatC(i,digits=2,flag="0"),".",formatC(j,digits=2,flag="0"),"\n",sep="")
>
>            }
>
>    }
>                                }
>
> I like to save what appears on the screen when I run using
> generate.index(10) as a character vector
>
> I used
> temp <- generate.index(10)
>
> but it didn't work.
>
> Could you provide some advice on this issue?
>
> Thanks in advance
>
> TM
>
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>



--
Jim Holtman
Cincinnati, OH
+1 513 247 0281

What the problem you are trying to solve?

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