Hi Michael, Try:
A-as.vector(B) Cheers, Anders. On Monday 06 March 2006 01:10 pm, Michael wrote: > Hi all, > > I want to substract vector B from A's each column... how can R do > that smartly without a loop? > > > A=matrix(c(2:7), 2, 3) > > A > > [,1] [,2] [,3] > [1,] 2 4 6 > [2,] 3 5 7 > > > B=matrix(c(1, 2), 2, 1) > > B > > [,1] > [1,] 1 > [2,] 2 > > > A-B > > Error in A - B : non-conformable arrays > > [[alternative HTML version deleted]] > > ______________________________________________ > R-help@stat.math.ethz.ch mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide! > http://www.R-project.org/posting-guide.html ______________________________________________ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
