Hi, I've run into a ridiculous problem I can't find any solutions for in the archives or help pages:
data(barley) cutYield <- with(barley, by(yield, variety, cut, breaks = c(0, 30, 60, 90))) As in this example, I'm using 'by' to return a factor for each level of another factor. The problem is that 'by' returns a list of the factors, and I need all these factors concatenated. No problem, I said: unlist(cutYield) which returns an 'integer' class object, so it's no longer a factor. The same happens with: do.call(c, cutYield) I could recreate the factor from the integer level codes returned above, but this is not good because this means redoing the job already done by the function called in 'by', making the code more prone to errors. Thanks in advance for any pointers, -- Sebastian ______________________________________________ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
