--- Berton Gunter <[EMAIL PROTECTED]> wrote:
> >
> > Here are a few alternatives:
> >
> > replace(a, is.na(a), 0) + b
> >
> > ifelse(is.na(a), 0, a) + b
> >
> > mapply(sum, a, b, MoreArgs = list(na.rm = TRUE))
> >
>
> Well, Gabor, if you want to get fancy...
>
> evalq({a[is.na(a)]<-0;a})+b
It's going into my tips file but what does it mean??
Thanks
>
> (and variants...)
>
> Cheers,
> Bert
>
>
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