Dear all,
Based on my question a few months ago
https://stat.ethz.ch/pipermail/r-help/2006-January/086952.html
and solved with
https://stat.ethz.ch/pipermail/r-help/2006-January/086955.html
https://stat.ethz.ch/pipermail/r-help/2006-January/086956.html
and from
https://stat.ethz.ch/pipermail/r-help/2006-January/086958.html
frac.fun <- function(x, den){
dec <- seq(0, den) / den
nams <- paste(seq(0, den), den, sep = "/")
sapply(x, function(y) nams[which.min(abs(y - dec))])
}
#######################
frac.fun(c(0, 1, 0.8266667, .066666, 0.2666666), 75)
Now, I have a dataset something like this:
a <-"1 0
1 0.095238095238095
1 0.214285714285714
-1 0.5
1 0.309523809523810
-1 0.0476190476190476
1 0.404761904761905
1 0.119047619047619
-1 0.214285714285714
-1 0.309523809523810
1 0
1 0
1 0.404761904761905
1 0.095238095238095
1 0.047619047619047
1 0.380952380952381
1 0.214285714285714
1 0.523809523809524
1 0
1 0.095238095238095"
First, I make it as fractions and then sorted.
I have played around to make it sort, but it didn't succes.
df <- read.table(textConnection(a))
library(MASS)
as.fractions(as.numeric(df[,2]))
cbind(table(df[,2], df[,1]), summary(as.factor(df[,2])))
table(frac.fun(as.numeric(df[,2]),42), df[,1])
> table(frac.fun(as.numeric(df[,2]),42), df[,1])
-1 1
0/42 0 4
13/42 1 1
16/42 0 1
17/42 0 2
21/42 1 0
22/42 0 1
2/42 1 1
4/42 0 3
5/42 0 1
9/42 1 2
>
How to make the result as sort (to increase) like this,
-1 1
0/42 0 4
2/42 1 1
4/42 0 3
5/42 0 1
9/42 1 2
13/42 1 1
16/42 0 1
17/42 0 2
21/42 1 0
22/42 0 1
Thank's for any help.
Best, Muhammad Subianto
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