On Fri, 2006-08-18 at 16:44 -0400, Rajarshi Guha wrote:
> Hi, I have a situation where I have a list of lists. Each list can
> contain elements of different types (but each one will be a scalar) say
> of double, integer or character.
>
> However the elements of each list are always in the same order:
>
> x <- list('a', 1, 2)
> y <- list('b', 3, 4)
> z <- list('c', 5, 6)
>
> a <- list(x,y,z)
>
> What I'd like to do is to convert a to a data.frame.
>
> Currently I am doing:
>
> b <- do.call(rbind, a)
>
> However, when I do b[,1] I get a list returned rather than a vector of
> characters and similarly for b[,2] and so on.
>
> I am clearly missing something, but how do I convert the list of lists
> to a data.frame where a column is represented as a vector rather than a
> list?
>
> Thanks,
How about:
> as.data.frame(sapply(a, rbind))
V1 V2 V3
1 a b c
2 1 3 5
3 2 4 6
or:
> as.data.frame(t(sapply(a, rbind)))
V1 V2 V3
1 a 1 2
2 b 3 4
3 c 5 6
depending upon how you wanted the columns versus rows to be structured.
HTH,
Marc Schwartz
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