> -----Original Message----- > From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] > On Behalf Of Jesse Albert Canchola > Sent: Friday, August 18, 2006 1:02 PM > To: r-help > Subject: [R] Permutations with replacement > > Is there a simple function or process that will create permutations with > replacement? > > I know that using the combinat package > > ###### begin R code ###### > > library(combinat) > > m <- t(array(unlist(permn(3)), dim = c(3, 6))) > > # we can get the permutations, for example 3!=6 > # gives us > > > m > [,1] [,2] [,3] > [1,] 1 2 3 > [2,] 1 3 2 > [3,] 3 1 2 > [4,] 3 2 1 > [5,] 2 3 1 > [6,] 2 1 3 > ###### end R code ########## > > I'd like to include the "with replacement possibilities" such as > > 1,1,3 > 1,1,2 > 2,3,3 > Isn't what you want just sampling with replacement?
x <- c(1,2,3) sample(x,3,replace=TRUE) Hope this is helpful, Dan Dan Nordlund Bothell, WA USA ______________________________________________ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
