Dear all,
After I work around, I found in my list of data with only one row which
need to remove or make it as matrix.
Here I write again my other toy example:
x <- list(matrix(1:20, 5, 4),matrix(1:20, 5, 4),matrix(1:20, 5,
4),matrix(1:20, 5, 4),matrix(1:20, 5, 4))
y <- list(c(1, -1, -1, 1, 1),c(1, -1, -1, -1, -1),c(1, 1, 1, 1, 1),c(1,
1, -1, 1, -1),c(-1, -1, -1, -1, -1))
## Thanks to Gabor Grothendieck for this trick.
## SIMPLIFY? SIMPLIFY >< simplify
xy.list <- mapply(cbind, x, y, SIMPLIFY=FALSE)
point.class <-
t(cbind(c(10,20,15,4,-1),c(21,10,15,34,-1),c(11,13,6,3,1),c(7,5,5,2,1),c(8,9,5,12,-1)))
class.diffsame <- points.neighb(as.matrix(point.class), xy.list, 5)
pd.class <- points.diff(class.diffsame,xy.list)
nc.test <- vector("list",length(pd.class))
for (i in 1:length(pd.class)) {
nc.test[[i]] <- pd.class[[i]]$point.diff
}
nc.test
# delete null/empty entries in a list
dff <- delete.NULLs(nc.test)
dff; str(dff)
> dff
[[1]]
[,1] [,2] [,3] [,4] [,5]
[1,] 1 6 11 16 1
[2,] 4 9 14 19 1
[3,] 5 10 15 20 1
[[2]]
[1] 1 6 11 16 1
[[3]]
[,1] [,2] [,3] [,4] [,5]
[1,] 3 8 13 18 -1
[2,] 5 10 15 20 -1
>
lapply(dff, nrow)
> lapply(dff, nrow)
[[1]]
[1] 3
[[2]]
NULL
[[3]]
[1] 2
>
#I can use
#dff[unlist(lapply(dff, nrow) == 1)] #2,3, etc
I have two questions here:
a. I need to remove dff[[2]]
b. How to make it as matrix (in list). I mean the result something like
[[1]]
[,1] [,2] [,3] [,4] [,5]
[1,] 1 6 11 16 1
[2,] 4 9 14 19 1
[3,] 5 10 15 20 1
[[2]]
[,1] [,2] [,3] [,4] [,5]
[1] 1 6 11 16 1
[[3]]
[,1] [,2] [,3] [,4] [,5]
[1,] 3 8 13 18 -1
[2,] 5 10 15 20 -1
Best, Muhammad Subianto
points.neighb <- function(p.class, list.nc, class.col) {
ntuples <- nrow(p.class)
instvec <- vector("list",length=ntuples)
for (i in 1:ntuples) {
# Thanks to Petr Pikal for this trick
instvec[[i]]$class.diff <- (p.class[i,class.col] -
list.nc[[i]][,class.col])!=0
instvec[[i]]$class.same <- (p.class[i,class.col] -
list.nc[[i]][,class.col])==0
}
instvec
}
points.diff <- function(p.class, list.nc) {
ntuples <- length(list.nc)
instvec <- vector("list",ntuples)
for (i in 1:ntuples) {
instvec[[i]]$point.diff <- list.nc[[i]][p.class[[i]]$class.diff,]
instvec[[i]]$point.same <- list.nc[[i]][p.class[[i]]$class.same,]
}
instvec
}
# Thanks to Jim Holtman for this trick
delete.NULLs <- function(x.list){
x.list[unlist(lapply(x.list, length) != 0)]
}
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